2q^2+9qr-35r^2=0

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Solution for 2q^2+9qr-35r^2=0 equation:


Simplifying
2q2 + 9qr + -35r2 = 0

Reorder the terms:
9qr + 2q2 + -35r2 = 0

Solving
9qr + 2q2 + -35r2 = 0

Solving for variable 'q'.

Factor a trinomial.
(2q + -5r)(q + 7r) = 0

Subproblem 1

Set the factor '(2q + -5r)' equal to zero and attempt to solve: Simplifying 2q + -5r = 0 Solving 2q + -5r = 0 Move all terms containing q to the left, all other terms to the right. Add '5r' to each side of the equation. 2q + -5r + 5r = 0 + 5r Combine like terms: -5r + 5r = 0 2q + 0 = 0 + 5r 2q = 0 + 5r Remove the zero: 2q = 5r Divide each side by '2'. q = 2.5r Simplifying q = 2.5r

Subproblem 2

Set the factor '(q + 7r)' equal to zero and attempt to solve: Simplifying q + 7r = 0 Solving q + 7r = 0 Move all terms containing q to the left, all other terms to the right. Add '-7r' to each side of the equation. q + 7r + -7r = 0 + -7r Combine like terms: 7r + -7r = 0 q + 0 = 0 + -7r q = 0 + -7r Remove the zero: q = -7r Simplifying q = -7r

Solution

q = {2.5r, -7r}

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